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Aleksandrowo (Wągrowiec Kūn)

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Aleksandrowo
—  Chng-thâu  —
Aleksandrowo is located in Pho-lân
Aleksandrowo
Aleksandrowo
Keng-hūi-tō͘: 52°53′N 17°28′E / 52.883°N 17.467°E / 52.883; 17.467
Kok-ka  Pho-lân
Séng Tōa Pho-lân
Kūn Wągrowiec
Kong-siā Wapno
Sî-khu CET (UTC 1)
 - Joa̍h-tang CEST (UTC 2)

Aleksandrowo sī chi̍t ê tī Pho-lân Kiōng-hô-kok Tōa Pho-lân Séng Wągrowiec Kūn Wapno Kong-siā ê chng-thâu.[1]

Chham-oa̍t

[siu-kái | kái goân-sí-bé]

Chham-khó

[siu-kái | kái goân-sí-bé]
  1. ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01. 
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