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Aleksandrów (Biłgoraj Kūn)

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Aleksandrów
—  Chng-thâu  —
Aleksandrów is located in Pho-lân
Aleksandrów
Aleksandrów
Keng-hūi-tō͘: 50°27′52″N 22°54′22″E / 50.46444°N 22.90611°E / 50.46444; 22.90611
Kok-ka  Pho-lân
Séng Lublin Séng
Kūn Biłgoraj Kūn
Kong-siā Aleksandrów Kong-siā
Sî-khu CET (UTC 1)
 - Joa̍h-tang CEST (UTC 2)

Aleksandrów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Lublin Séng Biłgoraj Kūn Aleksandrów Kong-siā ê chng-thâu.[1]