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[Suggestion] answer to "how many workers will I need?" for the README #124

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Aiyubi opened this issue Aug 3, 2016 · 5 comments
Closed

[Suggestion] answer to "how many workers will I need?" for the README #124

Aiyubi opened this issue Aug 3, 2016 · 5 comments

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@Aiyubi
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Aiyubi commented Aug 3, 2016 •
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Posting this here first so someone else can check my math first.

For rectangular areas that have optimal distances:

numberofworkers = Area_to_check / Area_of_circle * overlap_correction_factor * scan_delay / 15 minutes
with
Area_of_circle = pi * (70m)²
scan_delay = configvalue
overlap_correction_factor = (overlap_area/2 regular_area) / regular_area =  ( pi -2   pi ) / (pi) = 2 - 2/pi ~ 1.37

How come this correction factor?
overlap_area (last formular): http://mathworld.wolfram.com/Circle-CircleIntersection.html
devided by 2 because every overlap belongs to 2 circles

Some example calculation:

numberofworkers = Area_to_check / (pi*(70m)²) *1.37 * 10s / (15*60s)
Area_to_check = 96 km² (Wroclaw) = 96 * 10^6 m²

->96 workers (best some more to account calculation and delays)

So we see: 1 worker per km²
@theresthatguy
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This is very helpful. Thank you.

@Aiyubi
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Aiyubi commented Aug 3, 2016 •
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And now a try for hexagonal (same link as above):
overlap_area = (pi - 3/2*sqrt(3) *2) * 2
overlap_correction_factor ~ 1.17

Results:
numer_of_workers = (pi * radius²) /( pi * 70m²) * 1.17 * 10s / (15*60s) = (radius_in_km)² * 2.65

Example:
a radius of 5.5km is around 95km² and with the formular above would be ~80 workers
So we now have 80 instead of 95 workers cause of the reduced overlap.

@Eskof
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Eskof commented Aug 8, 2016

Hello @Aiyubi and thanks, I'm pretty noob with math. How may I calculate this with 2 coordinate?
Thanks

@Aiyubi
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Aiyubi commented Aug 8, 2016

@Eskof your /report tells you how many km² your area has

@modrzew
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modrzew commented Aug 9, 2016

Added in v0.5.0 IIRC. Thanks @Aiyubi!

@modrzew modrzew closed this as completed Aug 9, 2016
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@modrzew @Aiyubi @theresthatguy @Eskof