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What does network.activate do with liquid state machines? #85

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sitmo opened this issue Apr 17, 2016 · 1 comment
Open

What does network.activate do with liquid state machines? #85

sitmo opened this issue Apr 17, 2016 · 1 comment

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@sitmo
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sitmo commented Apr 17, 2016

I was wondering what network.activate does with a random liquid state machines topology.

Suppose I have 1 input and 1 output, and both both are connected to the 2 neurons (A,B) in the hidden layer. Additionally A and B are connected to each other.

layout

Will network.activate()..

  • feed I to A and B
  • also feed the output of (the previous activate() call of) A to B and visa versa
  • compute the output of A and B and then feed it to O?

If so, where does is keep the output state of the hidden neurons A,B? Can you access them? And will .standalone() keep track of those hidden states between calls?

@cazala
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cazala commented May 4, 2016

Sure, they will get the last activation of their input neurons. standalone should work fine. When the network is optimized (which is the behaviour by default) everything get stored in a huge array. If you want to access his data after training, you have to call myNetwork.restore() to pull all the data from the optimized array to the actual neuron instances. After this you can just navigate to the desired layer and neuron, and there you have values like activation which hold the last activation of that neuron.

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