Skip to content

abdeladim-s/pygptj

Repository files navigation

PyGPT-J

  • Python bindings for GPT-J ggml language models.
  • Almost the same API as pyllamacpp.

License: MIT PyPi version

Table of contents

Installation

  1. The easy way is to use the prebuilt wheels
pip install pygptj
  1. Build from source:
git clone git https://github.com/abdeladim-s/pygptj.git

CLI

You can run the following simple command line interface to test the package once it is installed:

pygtj path/to/ggml/model

Tutorial

Quick start

from pygptj.model import Model

model = Model(model_path='path/to/gptj/ggml/model')
for token in model.generate("Tell me a joke ?"):
    print(token, end='', flush=True)

Interactive Dialogue

You can set up an interactive dialogue by simply keeping the model variable alive:

from pygptj.model import Model

model = Model(model_path='/path/to/ggml/model')
while True:
    try:
        prompt = input("You: ", flush=True)
        if prompt == '':
            continue
        print(f"AI:", end='')
        for token in model.generate(prompt):
            print(f"{token}", end='', flush=True)
        print()
    except KeyboardInterrupt:
        break

Attribute a persona to the language model

The following is an example showing how to "attribute a persona to the language model" :

from pygptj.model import Model

prompt_context = """Act as Bob. Bob is helpful, kind, honest,
and never fails to answer the User's requests immediately and with precision. 

User: Nice to meet you Bob!
Bob: Welcome! I'm here to assist you with anything you need. What can I do for you today?
"""

prompt_prefix = "\nUser:"
prompt_suffix = "\nBob:"

model = Model(model_path='/path/to/ggml/model',
              prompt_context=prompt_context,
              prompt_prefix=prompt_prefix,
              prompt_suffix=prompt_suffix)

while True:
  try:
    prompt = input("User: ")
    if prompt == '':
      continue
    print(f"Bob: ", end='')
    for token in model.generate(prompt, antiprompt='User:'):
      print(f"{token}", end='', flush=True)
      print()
  except KeyboardInterrupt:
    break

API reference

You can check the API reference documentation for more details.

License

This project is licensed under the MIT License.