Charles Guillemet

How is learning OOP in C# for data scientists? OOP #CSharp #ProgrammingJourney #CodingChallenges Learning Object-Oriented Programming (OOP) can be a daunting task, especially if you're transitioning from a field like data science. I’ve walked this road myself and can relate to the feeling of being overwhelmed by the complexity and abstraction. Why OOP Can Be Challenging Coming from a data science background, which often heavily utilizes languages like Python, transitioning to a highly structured OOP language like C#... Read more: https://lnkd.in/dtWemxQH

How is learning OOP in C# for data scientists? OOP #CSharp #ProgrammingJourney #CodingChallenges Learning Object-Oriented Programming (OOP) can be a daunting task, especially if you're transitioning from a field like data science. I’ve walked this road myself and can relate to the feeling of being overwhelmed by the complexity and abstraction. Why OOP Can Be Challenging Coming from a data science background, which often heavily utilizes langu... Source: https://lnkd.in/dnAsyUUi #mymetric360

LeetCode 6. Zigzag Conversion The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility) P A H N A P L S I I G Y I R And then read line by line: "PAHNAPLSIIGYIR" Write the code that will take a string and make this conversion given a number of rows: string convert(string s, int numRows);   Example 1: Input: s = "PAYPALISHIRING", numRows = 3 Output: "PAHNAPLSIIGYIR" Example 2: Input: s = "PAYPALISHIRING", numRows = 4 Output: "PINALSIGYAHRPI" Explanation: P I N A L S I G Y A H R P I Example 3: Input: s = "A", numRows = 1 Output: "A" 𝐒𝐨𝐥𝐮𝐭𝐢𝐨𝐧 Edge case: if (numRows == 1) return s; This handles the scenario where the number of rows is 1. In such cases, the string remains unchanged because there’s no zigzag pattern—it's just a single row. 𝐈𝐧𝐢𝐭𝐢𝐚𝐥𝐢𝐳𝐚𝐭𝐢𝐨𝐧: List<StringBuilder> rows = newArrayList<>(numRows); for (inti=0; i < numRows; i ) { rows.add(newStringBuilder()); } This creates a list of StringBuilder objects, each representing a row in the zigzag pattern. 𝐅𝐢𝐥𝐥𝐢𝐧𝐠 𝐑𝐨𝐰𝐬: boolean goingDown=false; int currRow=0; for (char c : s.toCharArray()) { rows.get(currRow).append(c); if (currRow == 0 || currRow == numRows - 1) { goingDown = !goingDown; } currRow = goingDown ? 1 : -1; } Direction Handling: The variable goingDown is used to determine whether the current direction of filling is downward or upward. This direction toggles when you reach the top or bottom row. Row Update: Depending on the direction, currRow is incremented or decremented to move to the next row. 𝐁𝐮𝐢𝐥𝐝𝐢𝐧𝐠 𝐭𝐡𝐞 𝐑𝐞𝐬𝐮𝐥𝐭: StringBuilderres=newStringBuilder(); for (StringBuilder sb : rows) { res.append(sb); } return res.toString(); Concatenate all rows to form the final zigzag string and return it. 𝐓𝐢𝐦𝐞 𝐚𝐧𝐝 𝐬𝐩𝐚𝐜𝐞 𝐜𝐨𝐦𝐩𝐥𝐞𝐱𝐢𝐭𝐲 The time complexity is O(n), where n is the length of the string, since each character is processed once and inserted into one of the rows. The space complexity is also O(n) due to the space required for storing the characters in the rows list. Resources: Greg Hogg https://lnkd.in/gdgxKHaU AlgoJS https://lnkd.in/gtWxeC_n NeetCode https://lnkd.in/gYv_AU8D Follow Interview Prep for more. #dsa #coding #interview #programming

🚀 Exciting news! 🚀 A new release version 0.7.6 of the open-source Xray Maven Plugin is available now. This update brings two changes that will enhance your experience with the plugin. 🔄 One of the key updates in this release is the reordering of log and log level for report files. This improvement will make it easier for you to access and analyze the data generated by the plugin, helping you to track your test results more efficiently. 📊 Another significant enhancement is the... import test results always in the same order feature. This ensures consistency in how test results are imported, ... Link: https://lnkd.in/eNhk8YVD powered by Metropol Hub