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1966 Texas gubernatorial election

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1966 Texas gubernatorial election

← 1964 November 8, 1966 1968 ⊟
 
Nominee John Connally T. E. Kennerly
Party Democratic Republican
Popular vote 1,037,517 368,025
Percentage 72.8% 25.8%

County results
Connally:      50–60%      60–70%      70–80%      80–90%      >90%

Governor before election

John Connally
Democratic

Elected Governor

John Connally
Democratic

The 1966 Texas gubernatorial election was held on November 8, 1966, to elect the governor of Texas. Incumbent Democratic governor John Connally was easily reelected to a third term, winning 73% of the vote to Republican T. E. Kennerly's 26%. Connally swept all 254 counties in this election and was inaugurated for his third term on January 17, 1967.

The election is, to date, the last time that a candidate for Governor of Texas won more than 70% of the vote, as well as the last in which a candidate won every county. As of 2024, Randall, Ochiltree, and Smith counties have not voted for the Democratic candidate since this election.

Primaries

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Republican

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Republican primary results[1]
Party Candidate Votes %
Republican T. E. Kennerly 49,568 100.00%
Total votes 49,568 100.00%

Democratic

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Democratic primary results
Party Candidate Votes %
Democratic John Connally (incumbent) 932,641 74.29%
Democratic Stanley C. Woods 291,651 23.23%
Democratic Johnnie Mae Hackworthe 31,105 2.48%
Total votes 1,255,400 100.00%

Results

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General election results
Party Candidate Votes %
Democratic John Connally (incumbent) 1,037,517 72.76%
Republican T. E. Kennerly 368,025 25.81%
Constitution Tommye Gillespie 10,454 0.73%
Conservative Bard Logan 9,810 0.69%
Total votes 1,425,861 100.00%
Democratic hold

References

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  1. ^ "Texas Almanac". Archived from the original on November 19, 2015. Retrieved August 6, 2015.