Jump to content

Asiab Jub-e Farmanfarma

Coordinates: 34°58′43″N 47°34′05″E / 34.97861°N 47.56806°E / 34.97861; 47.56806
From Wikipedia, the free encyclopedia
Asiab Jub-e Farmanfarma
اسياب جوب فرمانفرما
village
Asiab Jub-e Farmanfarma is located in Iran
Asiab Jub-e Farmanfarma
Asiab Jub-e Farmanfarma
Coordinates: 34°58′43″N 47°34′05″E / 34.97861°N 47.56806°E / 34.97861; 47.56806
Country Iran
ProvinceKermanshah
CountySonqor
BakhshCentral
Rural DistrictGavrud
Population
 (2006)
 • Total
145
Time zoneUTC 3:30 (IRST)
 • Summer (DST)UTC 4:30 (IRDT)

Asiab Jub-e Farmanfarma (Persian: اسياب جوب فرمانفرما, also Romanized as Āsīāb Jūb-e Farmānfarmā; also known as Jūb-e Farmānfarmā)[1] is a village in Gavrud Rural District, in the Central District of Sonqor County, Kermanshah Province, Iran. At the 2006 census, its population was 145, in 32 families.[2]

References

[edit]
  1. ^ Asiab Jub-e Farmanfarma can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3802277" in the "Unique Feature Id" form, and clicking on "Search Database".
  2. ^ "Census of the Islamic Republic of Iran, 1385 (2006)" (Excel). Statistical Center of Iran. Archived from the original on 2011-09-20.