Jump to content

2022 Australian Open – Wheelchair women's singles

From Wikipedia, the free encyclopedia
Wheelchair women's singles
2022 Australian Open
Final
ChampionNetherlands Diede de Groot
Runner-upNetherlands Aniek van Koot
Score6–1, 6–1
Details
Draw8
Seeds2
Events
Singles men women boys girls
Doubles men women mixed boys girls
WC Singles men women quad
WC Doubles men women quad
← 2021 · Australian Open · 2023 ⊟

Defending champion Diede de Groot[1] defeated Aniek van Koot in the final, 6–1, 6–1 to win the women's singles wheelchair tennis title at the 2022 Australian Open. It was the first step in an eventual Grand Slam for de Groot.

Seeds

[edit]
  1. Netherlands Diede de Groot (champion)
  2. Japan Yui Kamiji (quarterfinals)

Draw

[edit]

Key

[edit]

Bracket

[edit]
Quarterfinals Semifinals Final
               
1 Netherlands Diede de Groot 6 6
United States Dana Mathewson 2 1
1 Netherlands Diede de Groot 6 7
WC United Kingdom Lucy Shuker 0 5
China Zhu Zhenzhen 2 2
WC United Kingdom Lucy Shuker 6 6
1 Netherlands Diede de Groot 6 6
Netherlands Aniek van Koot 1 1
South Africa Kgothatso Montjane 6 64 7
Netherlands Jiske Griffioen 1 77 5
South Africa Kgothatso Montjane 3 4
Netherlands Aniek van Koot 6 6
Netherlands Aniek van Koot 7 7
2 Japan Yui Kamiji 5 5

References

[edit]
  1. ^ "2021 Australian Open: de Groot, Davidson are 2021 Champions". Yonex. 11 January 2022. Retrieved 11 January 2022.
[edit]