1803 Georgia gubernatorial election
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The 1803 Georgia gubernatorial election was held on 24 November 1803 in order to elect the governor of Georgia. Incumbent Democratic-Republican governor John Milledge won re-election against Solomon Wood in a Georgia General Assembly vote.[1]
General election
[edit]On election day, 24 November 1803, incumbent Democratic-Republican governor John Milledge won re-election against his opponent Solomon Wood. Milledge was sworn in for his first full term on 25 November 1803.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | John Milledge (incumbent) | 65 | 91.55 | |
| Solomon Wood | 6 | 8.45 | ||
| Total votes | 71 | 100.00 | ||
| Democratic-Republican hold | ||||
References
[edit]- ^ "Georgia 1803 Governor". Tufts Digital Collations and Archives. A New Nation Votes: American Election Returns 1787–1825. Tufts University. Retrieved 4 December 2023.
- ^ "GA Governor". ourcampaigns.com. 18 July 2022. Retrieved 4 December 2023.
- ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
Categories:
- Georgia (U.S. state) gubernatorial elections
- 1803 United States gubernatorial elections
- 1803 Georgia (U.S. state) elections
- 1803 in Georgia (U.S. state)
- Indirect elections
- November 1803 events
- 1800s in Georgia (U.S. state)
- 1800s Georgia (U.S. state) elections
- 1803 elections
- 1803 elections in North America
- 1803 elections in the United States
- United States gubernatorial elections in the 1800s
- Government of Georgia (U.S. state)