2018 Boyd Tinsley Clay Court Classic – Doubles

Jovana Jakšić and Catalina Pella were the defending champions, but decided not to participate.

Doubles
2018 Boyd Tinsley Clay Court Classic
Final
ChampionsUnited States Sophie Chang
United States Alexandra Mueller
Runners-upUnited States Ashley Kratzer
United States Whitney Osuigwe
Score3–6, 6–4, [10–7]
Events
Singles Doubles
← 2017 · Boyd Tinsley Clay Court Classic · 2019 →

Sophie Chang and Alexandra Mueller won the title after defeating Ashley Kratzer and Whitney Osuigwe 3–6, 6–4, [10–7] in the final.

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   I Bara
  M Duque Mariño
6 6
    K Cartwright
  K Pierre-Louis
3 1 1   I Bara
  M Duque Mariño
2 7 [10]
WC   A Smith
  N Subhash
6 6 WC   A Smith
  N Subhash
6 5 [5]
    M Mateas
  R Yurovsky
2 4 1   I Bara
  M Duque Mariño
6 4 [4]
3   S Chang
  A Mueller
6 6 3   S Chang
  A Mueller
1 6 [10]
    L Chirico
  F Di Lorenzo
3 3 3   S Chang
  A Mueller
7 6
    P Januskova
  R Ozaki
4 6 [7]   C Rosatello
  AS Sánchez
5 2
    C Rosatello
  AS Sánchez
6 3 [10] 3   S Chang
  A Mueller
3 6 [10]
    V Duval
  J Loeb
6 4 [10]   A Kratzer
  W Osuigwe
6 4 [7]
    Q Gleason
  A Weinhold
2 6 [8]   V Duval
  J Loeb
6 62 [10]
    A Kratzer
  W Osuigwe
6 6   A Kratzer
  W Osuigwe
3 77 [12]
4   PC Gonçalves
  S Marand
3 4   A Kratzer
  W Osuigwe
6 2 [12]
    J Cristian
  K Day
1 3   I Neel
  M Sanchez
4 6 [10]
    I Neel
  M Sanchez
6 6   I Neel
  M Sanchez
6 1 [20]
    R McAdoo
  K Stewart
6 4 [7] 2   A Guarachi
  E Routliffe
2 6 [18]
2   A Guarachi
  E Routliffe
2 6 [10]

References

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