1879 Rhode Island gubernatorial election

1879 Rhode Island gubernatorial election
	County results; Zandt: 50–60% 60–70% 70–80% 80–90%
Governor before election; Charles C. Van Zandt; Republican	Elected Governor ; Charles C. Van Zandt; Republican

The 1879 Rhode Island gubernatorial election was held on April 2, 1879. Incumbent Republican Charles C. Van Zandt defeated Democratic nominee Thomas W. Segar with 62.09% of the vote.

General election

Candidates

Major party candidates

Charles C. Van Zandt, Republican
Thomas W. Segar, Democratic

Other candidates

Samuel Hill, Independent

Results

1879 Rhode Island gubernatorial election^[1]
Party		Candidate	Votes	%
	Republican	Charles C. Van Zandt (incumbent)	9,717	62.09%
	Democratic	Thomas W. Segar	5,506	35.18%
	Greenback	Samuel Hill	318	2.03%
Majority			4,211
Turnout
	Republican hold		Swing

References

^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved November 1, 2020.

[1] Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved November 1, 2020.

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